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Dr.Sprock
Boulder climber
I'm James Brown, Bi-atch!
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Jun 10, 2013 - 02:47am PT
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if we all pitch in, we could buy a rest home with a climbing wall.
only problem would be finding nurses,
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cowpoke
climber
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Jun 10, 2013 - 06:55am PT
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the latest and greatest:
Some things to consider:
1. there are nearly three times as many Supertopo respondents in their 50s as there are in their 40s (67 vs. 24).
2. there are nearly as many respondents in their 30s (23) as there are in their 40s, but both are still well behind respondents in their 60s (33)
3. the median age of respondents is 12.4 years older than the median age in Canada (40.6 in 2010) and 15.9 years older than the median age in the US (37.1).
4. cheers, Don, for standing tall at the tail of the distribution -- freaking awesome!
[One fun idea: someone could overlay a timeline onto this histogram providing an abbreviated history of climbing. But, the timeline would run from right to left...and given our oldest respondent (thus far), perhaps the first dates would come from a time when this respondent was in his late teens/early 20's. We would end up with an abbreviated timeline of historical climbing accomplishments across these generations. For example, if the first year at the far right of the graph was 1950 (at which time Don Lauria was 17), then Steck-Salathe FA could be noted. By the time the timeline got down to the 30 yr olds, there would be things like Lynn Hill's FFA of the nose; and, by the far right we'd have things like Honnold's solos (for those not in their teens yet!)...obviously, I left out tons in between and only mentioned ditch big events, but you get the idea.]
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tradmanclimbs
Ice climber
Pomfert VT
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Jun 10, 2013 - 07:33am PT
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so at 51 i am a youngster on this site :)
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tinker b
climber
the commonwealth
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Jun 10, 2013 - 07:36am PT
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for the research, 40 year old female. my best effort to keep the depends ads off the side bar.
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Don Lauria
Trad climber
Bishop, CA
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Jun 10, 2013 - 11:41am PT
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Glen Dawson (first ascent of east face of Mt Whitney with Clyde, Underhill, and Eichorn) turned 101 on June 3rd. Still has his book store in LA.
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FRUMY
Trad climber
SHERMAN OAKS,CA
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Jun 10, 2013 - 11:50am PT
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Glen Dawson ---- What a great guy.
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Don Lauria
Trad climber
Bishop, CA
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Jun 10, 2013 - 11:53am PT
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Just thought I'd throw in a photo from 1931 - the year before I was born.
Here they are: Eichorn, Clyde, Underhill, and Dawson.
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Alexey
climber
San Jose, CA
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Jun 10, 2013 - 12:01pm PT
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56
started climbing at 43
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cowpoke
climber
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Jun 10, 2013 - 12:01pm PT
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^^^would be soooo cool if Dawson would post so we could include him.
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Don Lauria
Trad climber
Bishop, CA
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Jun 10, 2013 - 12:05pm PT
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Here's the Belgian kid who was surprised to find out Donini was older than dirt.
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JEleazarian
Trad climber
Fresno CA
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Jun 10, 2013 - 01:18pm PT
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Jogill,
Have you considered the possibilities of children of age 1?
John
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jogill
climber
Colorado
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Jun 10, 2013 - 03:26pm PT
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OK, Wizard A = 36
and the kids are 1, 6, 6
or
2, 2, 9
I liked it better when you were 88!
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Gunkie
Trad climber
East Coast US
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Jun 10, 2013 - 03:33pm PT
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Apparently, I'm almost exactly Johnny Depp's age (50, he's a few weeks older) and I share my birth date with Neil Armstrong.
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Big Mike
Trad climber
BC
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Jun 10, 2013 - 03:53pm PT
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I'm 35 and currently feel a little bit older.. Lol i'm working on it...
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shady
Trad climber
hasbeen
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Jun 10, 2013 - 10:43pm PT
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Big Mike...
I'm working on it..
FWIW...
Don't stop! When you stop working on it, they put you in a Big Mike size box, and cover it with dirt.
;)
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rgold
Trad climber
Poughkeepsie, NY
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Jun 10, 2013 - 10:44pm PT
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Well, I've thought about the wizards problem and reduced it to checking a finite number of possibilities, a check which I am not willing to do either by hand or by writing a program to do it for me. What follows is an analysis that might catch the fancy of the odd lurking math geek, but will not be of interest to anyone else. Scroll on...
A way to search for solutions is to consider all possible bus numbers, for each bus number B enumerate all possible integer partitions of B, (http://en.wikipedia.org/wiki/Partition_%28number_theory%29); and for each such integer partition associate the wizard age obtained by multiplying together all of the partition parts.
Call an age A (B,n)-ambiguous if there are two different factorizations of A, each with n factors, n at least 3, such that in both cases the sum of the factors is B. (We insist on n at least three because knowledge of the bus number, the wizard's age, and the fact that there are two children is enough to determine the children's ages by solving a quadratic equation.)
A solution to the problem would correspond to a bus number B whose list of partitions contains but a single (B,n)-ambiguous age. (Note that there could be a (B,n)-ambiguous age and a (B,m)-ambiguous age with n not equal to m, and if this happens then the bus number B is not a candidate for the solution.)
John's first example has B=14, with 72 a (14,3)-ambiguous age. The (14,3) ambiguity of 72 is established by the children's age possibilities (2,6,6) and (3,3,8). John's second example has B=13, with 36 a (13,3)-ambiguous age. The (13,3)-ambiguity of 36 is established by the children's age possibilities (1,6,6) and (2,2,9). But neither of these can yet be considered a solution, because we still have to be shown that there cannot be another (14, m)-ambiguous age, respectively (13,m)-ambiguous age, with m > 3. There are, for example, 101 integer partitions of 13 according to Wolfram Alpha, and although a number of these can be eliminated, there still appears to be quite a few to check. (A computer program would make short work of it of course.)
There is one bit of good news: call a bus number B bad if among its list of partitions are partitions whose product determines two different (B,n)-ambiguous ages. If B is bad, then so are all bus numbers greater than B. This is because a (B,n)-ambiguous age is also going to be a (B+1, n+1)-ambiguous age---just add a 1 year-old child to the list of parts defining the (B,n)-ambiguous age. What this means is that if, for any reason, we discover a bus number to be bad, then all larger bus numbers are also going to be bad and so we only have to look for a solution among smaller bus numbers.
All bus numbers are not bad; for example B=1 is not bad (B=1 works mathematically but corresponds to a 1 year-old wizard with a 1 year-old son, which is not exactly the kind of solution we're looking for.) The point is that since not all bus numbers are bad, there must be a smallest bad bus number, and if there is a solution it must occur for bus numbers smaller than the smallest bad one. This guarantees that a search of finite length will either determine that there is no solution or else determine what the solution(s) is (are). In other words, there is a definitive answer or answers to the question that can be determined in a finite number of steps.
There is a subtlety to the problem statement which I haven't accounted for. Wizard B knows the bus number but we do not, yet we are supposed to find the age of Wizard A. I've written above as if it is possible that there is more than one bus number that will work and so more than one possible age for Wizard A. But the problem wording suggest that in fact there is only one correct age for Wizard A. This fact, if it is true, would emerge from enumerating all possibilities corresponding to the bus numbers less than the least bad one.
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LilaBiene
Trad climber
Technically...the spawning grounds of Yosemite
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Jun 10, 2013 - 10:45pm PT
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As a confirmed relativist, I always have to THINK about the answer to this question...lol.
43
Happy and excited to be alive, finally healthy and chasing down a new passion. Spooked here and there that I seem to have made it through what took out both Dolt and his mother before him...but all the stronger for it, and for having "found" both of my birth parents and seeing each of their unique strengths reflected in me.
Hope to live my life worthy of being their offspring. I've got some ideas...
;D
P.S. Frank Hoover lurks...what a twinkle he has in his eyes!
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jogill
climber
Colorado
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Jun 10, 2013 - 10:49pm PT
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See what I mean? The kid's brain runs circles around me!
Oh, to be a mere youth of 69.5 !
;>)
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looks easy from here
climber
Ben Lomond, CA
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Jun 16, 2013 - 02:03am PT
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only problem would be finding nurses
My wife's a nurse, and a climber, so she'd fit right in. Maybe not much help though, since she specializes in the beginning of life, not the end.
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AP
Trad climber
Calgary
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Jun 16, 2013 - 08:41pm PT
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55. Maybe we need a system including age and climbing grade. 55*10(as in 5.10)=550. Donini could get 69*11 so he would be way older.
We can appreciate why the search for the Fountain of Youth was a big deal.
Go to Skaha sometime and you will likely see at least one pensioner sending 5.11 or 5.12
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