Weather Forecast ( explanation please )

Search
Go

Discussion Topic

Return to Forum List
This thread has been locked
Messages 1 - 8 of total 8 in this topic
John Moosie

climber
Beautiful California
Topic Author's Original Post - Jan 22, 2009 - 08:44pm PT
This morning I woke up and it was raining. It had been raining all night. I look at the forecast for Yosemite, and it said 80 percent chance of rain. It says 50 percent chance of rain tonight. It is still raining. The radar looks like it will clear out fairly soon.

My question is, why 80 percent. The mornings forecast was posted at about 7 am. It was raining. It had been raining for a number of hours.

Can someone explain the percentages?
Toker Villain

Big Wall climber
Toquerville, Utah
Jan 22, 2009 - 08:54pm PT
Forecasts are often not locally based but generated from computer models that process multiple data sources.
TGT

Social climber
So Cal
Jan 22, 2009 - 09:06pm PT
My understanding (might be mislead) is that the % number is the predicted coverage for a given forecast area and probability, so 80% means that most of a given forecast area has a high probability it will get significant rain. 20 % of that area could still get nothing.

A combination of both probability and coverage of a given area.

Reilly

Mountain climber
Monrovia, CA
Jan 22, 2009 - 09:07pm PT
"why 80 percent"
'cause that's what it said on the bottle he was hittin' off of
Captain...or Skully

Social climber
North of the Owyhees
Jan 22, 2009 - 10:07pm PT
Uh, They don't have windows at the weather center........
Maybe.
John Moosie

climber
Beautiful California
Topic Author's Reply - Jan 22, 2009 - 10:17pm PT
Thats what I thought too skully. haha. I use to work on an orchard and we had a contract with a meteorologist. He said he would always go outside before making his forecast for the day.

I think Piton and TGT have it basically. It is a computer giving a percentage over a given area. What is strange is that Yosemite has multiple data points for rainfall totals and it seems like a computer would have read these and said.. aha... its raining there. Ipso facto.. 100 percent chance of rain today.
TradIsGood

Chalkless climber
the Gunks end of the country
Jan 22, 2009 - 10:57pm PT
You most commonly get two things from the weather service:
 Current Conditions
 Forecasts

Current conditions typically are reported from airports near the hour and occasionally when there is a significant change. By the time you get them, they are "slightly historical current conditions" since they are slight stale observations.

The weather service also issues a whole slew of forecasts - some scheduled and others as needed (advisories and warnings, for example).

Area forecasts are issued 3 times per day IIRC.

Non-governmental forecasters offer "probability of precipitation" forecasts, temperature forecasts, etc. Many charge for specific forecasts - especially to the financial services industry.

Finally, the NOAA will typically err on the bad weather side in their forecasts. They got sued by a widow many years back whose husband's boat sank in un-forecast bad weather. They lost and had to pay damages.
hagerty

Social climber
A Sandy Area South of a Salty Lake
Jan 23, 2009 - 01:01am PT
A probability of precipitation or POP of 40% doesn't mean that it will rain 40% of the day, or that rain will fall on 40% of your area or that it rained 40 times out of 100 on that particular day in the past (that is a climatological forecast). It also says nothing about how much rain or snow will occur.

A POP of 40% means that the forecasters have calculated that in 100 similar weather situations, rain has fallen 40 times in the forecast area. POP is for any point in your forecast area, not the whole area. So, for instance, a POP of 90% for rain means that 9 times out of 10 when this weather situation is predicted, you ought to get rain somewhere in the forecast area, e.g., at your home, playground or at the airport.

Mathematically, PoP is defined as follows:
PoP = C x A where "C" = the confidence that precipitation will occur somewhere in the forecast area, and where "A" = the percent of the area that will receive measurable precipitation, if it occurs at all.

So... in the case of the forecast above, if the forecaster knows precipitation is sure to occur ( confidence is 100% ), he/she is expressing how much of the area will receive measurable rain. ( PoP = "C" x "A" or "1" times ".4" which equals .4 or 40%.)

But, most of the time, the forecaster is expressing a combination of degree of confidence and areal coverage. If the forecaster is only 50% sure that precipitation will occur, and expects that, if it does occur, it will produce measurable rain over about 80 percent of the area, the PoP (chance of rain) is 40%. ( PoP = .5 x .8 which equals .4 or 40%. )

In either event, the correct way to interpret the forecast is: there is a 40 percent chance that rain will occur at any given point in the area.
Messages 1 - 8 of total 8 in this topic
Return to Forum List
 
Our Guidebooks
spacerCheck 'em out!
SuperTopo Guidebooks

guidebook icon
Try a free sample topo!

 
SuperTopo on the Web

Recent Route Beta